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CGP EDU Academic Team
Published on: August 14, 2026
The standard enthalpies of formation of CO 2 (g), H 2 O(l) and glucose(s) at 25ºC are –400 kJ/mol, –300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25ºC is
Text Solution
Verified by ExpertsThe correct answer is:
C
C 6 H 12 O 6 (s) + 6O 2 (g) ⎯→ 6CO 2 (g) + 6H 2 O( 
)
Δ C H = 6 × Δ f H (CO 2 ) + 6 Δ f H (H 2 O) – Δ f H (C 6 H 12 O 6 ) – 6 Δ f (O 2 ,g)
= 6 × (–400 – 300) – (–1300) – 0 = – 4200 + 1300 = – 2900 KJ/ mol
For one gram of glucose, enthalpy of combustion = – 
= –16.11 KJ/g.
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